Question

(x + 1Xx+ 2 xx + 3 Xx + 4)-8=0
​

Answer 1

please open the given above answer..,

x(x−1)(x+2)(x−3)+8=0

⇒(x

2

−x)(x

2

+(2−3)x+2×−3)+8=0

⇒(x

2

−x)(x

2

−x−6)+8=0

⇒x

4

−x

3

−6x

2

−x

3

+x

2

+6x+8=0

⇒x

4

−2x

3

−5x

2

+6x+8=0

Let f(x)=x

4

−2x

3

−5x

2

+6x+8=0

Let x=−1⇒f(−1)=(−1)

4

−2(−1)

3

−5(−1)

2

+6(−1)+8=0

=1+2−5−6+8=0

∴x=−1 is one root of the above equation.