Question

x^2-1=0 in roster form

Answer 1

➡HERE IS YOUR ANSWER⬇

Now,

${x}^{2} - 1 = 0 \\ \\ or \: \: (x + 1)(x - 1) = 0 \\ \\ so \: \: x = - 1 \: \: and \: \: x = 1$

Therefore the solution set in roster form be (-1,1).

⬆HOPE THIS HELPS YOU⬅

Answer 2

X^2-1=0
(x+1)(x-1)=0
x=1,-1