Question

x^2 + 1=0.... what are the roots​

Answer 1

Answer:

x = $\pm i$

Step-by-step explanation:

Given that -

x² + 1 = 0

On comparing the given equation with the standard form of quadratic equation ax² + bx + c = 0, we get -

a = 1, b = 0, c = 1

Discriminant = b² - 4ac

⇒ D = (0)² - 4 * 1 * 1

⇒ D = -4

∴ D < 0

Since, discriminant is negative, the roots can not be found. Therefore, we will go for following method -

$x {}^{2} + 1 = 0 \\ \\ \implies (x +i )(x - i ) = 0 \\ \\ \implies x = i \: \: or \: - i \\ \\ \boxed{ \bf \implies x = \pm i}$

Hence, the answer is x = $\pm i$