Question

(x^2 + 1)^2 - x^2 = 0 has how many real roots? ​

Answer 1

Step-by-step explanation:

Clearly the given equation is bi - quadratic .

So it will have at most 4 zeros......

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Answer 2

Step-by-step explanation:

(x^2+1)^2-x^2=0

(x^2+1)^2=x^2

rooting on both sides

we get

x^2+1=x x^2+1=-x

x^2-x+1=0 x^2+x+1=0

det of equations is less than zero

hence they have imaginary

Note :-----

The classification of the roots of the equation, based on the discriminant 'D' is as follows:

(i) The roots are real and equal id D = 0.

(ii) The roots are real and unequal if D > 0.

(iii) The roots are unreal if D < 0.