Question

x^2-(1+√2)x+√2=0
this is a tenth class question kindly help

Answer 1

Given x^2 - (1 + root 2) x + root 2 = 0

           x^2 - x - root 2 x + root 2 = 0

           x(x-1) - root 2(x - 1) = 0

           x - root 2 = 0 (or) x - 1 = 0

           x = root 2 (or) x = 1.


Hope this helps!          

Answer 2

I hope this will satisfy you