X^2 (1+√2)x + √2 =0 x€q
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Step-by-step explanation:
⇒ The give quadratic equation is 2x
2
+3ix+2=0, comparing it with ax
2
+bx+c=0
⇒ We get, a=2,b=3i,c=2
⇒ x=
2a
−b±
b
2
−4ac
=
2(2)
−3i±
(3i)
2
−4(2)(2)
=
4
−3i±
9i
2
−16
=
4
−3i±
−9−16
[ Since, i
2
=−1 ]
=
4
−3i±
−25
=
4
−3i±5i
⇒ x=
4
−3i+5i
and x=
4
−3i−5i
∴ x=
2
i
and x=−2i
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