x^2-1-2a-a^2 का गुणनखंड निकाले
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x^2 - ( 1+2a +a^2)
x^2-(1+a)^2 using identity a^-b^2
(x+1+a)(x-1-a)
x^2-(1+a)^2 using identity a^-b^2
(x+1+a)(x-1-a)
Answered by
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Given x^2 - 1 - 2a - a^2
= x^2 - (1 + 2a + a^2)
= x^2 - (1 + a)^2
We know that a^2 - b^2 = (a+b)(a-b)
= x + (1+a) (x - (1+a).
= (x + a + 1)(x - a - 1).
Hope this helps!
= x^2 - (1 + 2a + a^2)
= x^2 - (1 + a)^2
We know that a^2 - b^2 = (a+b)(a-b)
= x + (1+a) (x - (1+a).
= (x + a + 1)(x - a - 1).
Hope this helps!
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