Question

x^2+(1-2i)x-2i=0 solve by factorization method

Answer 1

Hey there!

x² + x - 2ix - 2i

x ( x + 1 ) - 2i ( x + 1 )

( x - 2i ) ( x + 1 ) = 0

Hope my answer helps!

Answer 2

Answer :

Given,

x² + (1 - 2i)x - 2i = 0

or, x² + x - 2ix - 2i = 0

or, x (x + 1) - 2i (x + 1) = 0

or, (x + 1) (x - 2i) = 0

Then,

either x + 1 = 0 or, x - 2i = 0

=> x = - 1, 2i

Therefore, the required solution be

x = - 1, 2i

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