Question

x^2-1/2x-1/2=0 find the nature of the roots of the following quadratic equation​

Answer 1

hope this will help you

Answer 2

$\huge{\mathcal{\blue{\underline{\underline{\pink{HeYa!!!}}}}}}$

${\large{\purple{\mathbb{ANSWER}}}}$

☆ Given quadratic equation:-

• x²-1/2x-1/2 = 0.

☆ To find:-

• Nature of the roots.

☆ Now,

=》 x²-1/2x-1/2 = 0

=》 2x²-x-1/2 = 0

{By Taking LCM}

=》 2x²-x-1 = 0×2.

${\small{\blue{\boxed{=》\:\:2xsquare-x-1\:=\:0}}}}$

☆ So,

Discriminant (d)

${\large{\red{\boxed{=\:\:bsquare-4ac}}}}$

☆ Also,

We know that

• If d=0 then roots are real and equal.

• If d<0 Then real roots does not exist.

• If d>0 Then roots are real and distinct.

☆ Therefore,

In this case,

=》 d = (-1)²-4(2)(-1).

=》 d = 1-(-8)

=》 d = 1+8

${\large{\blue{\boxed{=》\:\:d\:=\:9}}}}$

So d>0 therefore the given quadratic equation have real (non-negative) and distinct roots in nature.

Hope this will help you if it HELPS then plz mark my answer as BRAINLIEST.

And remember to always keep a smile on face:)

$<marquee>✌✌THANKS✌✌</marquee>$