Math, asked by krishnagupta2207050, 10 months ago

X - 2 = 1/3x
Find the values of
X2 + 1/9x2
X4 + 1/81x4


krishnagupta2207050: Can u show the question

Answers

Answered by sherya1349
9

Step-by-step explanation:

x_2=1/3x

x_1/3x=2

3x_x=6

2x=6 then,

x=3,

putting the value of x=3 in i eq

x2=1/9×2

6=1/9×2

54=2=27

putting the value of x=3 in ii eq

3×4=1/81×4

12×81=4

972=2=243


krishnagupta2207050: It's wrong
Answered by pinquancaro
26

x^2+\frac{1}{9}x^2=10

x^4+\frac{1}{81}x^4=82

Step-by-step explanation:

Given : Equation x-2=\frac{1}{3}x

To find : The values of expression ?

Solution :

First we solve the equation,

x-\frac{1}{3}x=2

\frac{3x-x}{3}=2

\frac{2x}{3}=2

x=\frac{2\times 3}{2}

x=3

1) The expression is x^2+\frac{1}{9}x^2

x^2+\frac{1}{9}x^2=(3)^2+\frac{1}{9}(3)^2

x^2+\frac{1}{9}x^2=9+\frac{1}{9}\times 9

x^2+\frac{1}{9}x^2=9+1

x^2+\frac{1}{9}x^2=10

2) The expression is x^4+\frac{1}{81}x^4

x^4+\frac{1}{81}x^4=(3)^4+\frac{1}{81}(3)^4

x^4+\frac{1}{81}x^4=81+\frac{1}{81}\times 81

x^4+\frac{1}{81}x^4=81+1

x^4+\frac{1}{81}x^4=82

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