Question

x^2-1
find the zeros of the following polynomial and find the zeros of the product​

Answer 1

$\small \bf \red{hey \: mate \: here \: is \: ur \: ans} \\ \\ \small \bf \red{ \huge \: solution} \\ \\ \small \bf \red{ {x}^{2} - 1 } \\ \\ \small \bf \red{as \: we \: can \: write \: } \\ \\ \small \bf \red{( {x)}^{2} - ( {1)}^{2} } \\ \\ \small \bf \red{using \: to \: this \: identity \: } \\ \\ \small \bf \red{ {a}^{2} - {b}^{2} = (a + b)(a - b) } \\ \\ \small \bf \red{(x + 1)(x - 1) = 0} \\ \\ \small \bf \red{x = - 1} \\ \\ \small \bf \red{and} \\ \\ \small \bf \red{x = 1 \: \: ans}$