Question

x^2-1 is always divisible by 8 if x is a/an
a) whole number
b) natural number
c) odd integer
d) even integer​

Answer 1

Answer:

natural number

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

x^2-1=(x-1)(x+1)

x=3

(x-1)(x+1)=2*4=8 divisible by 8

x=7

(x-1)(x+1)=6*8 divisible by 8

x=-15

(x-1)(x+1)=-16*-15 divisible by 8

x=-21

(x-1)(x+1)=-22*-20 divisible by 8

option c odd integer