x^2+1/x^2=14 , thenfind the value of x^2-1/x^2
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( x + 1/x )² = x² + 1/x² + 2 × x × 1/x
( x + 1/x )² = 14+2 = 16
x + 1/x = √16 = 4 -------------1
now ,
( x - 1/x )² = x² + 1/x² - 2 × x × 1/x
( x - 1/x )² = 14-2
x - 1/x = √12 = 2√3 -------------2
adding equation 1 and 2 ,
x + 1/x + x - 1/x = 4 + 2√3
2x = 4 + 2√3
x = 2 + √3
therefore
x^2-1/x^2 = (2 + √3)² - 1/(2 + √3)²
x² - 1/x² =[ (7 + 4√3 ) (7 + 4√3 ) -1 ]/(7 + 4√3 )
x² - 1/x² = (97 + 56√3 -1 ) / (7 + 4√3 )
x² - 1/x² =( 96 + 56√3 ) / (7 + 4√3 )
( x + 1/x )² = 14+2 = 16
x + 1/x = √16 = 4 -------------1
now ,
( x - 1/x )² = x² + 1/x² - 2 × x × 1/x
( x - 1/x )² = 14-2
x - 1/x = √12 = 2√3 -------------2
adding equation 1 and 2 ,
x + 1/x + x - 1/x = 4 + 2√3
2x = 4 + 2√3
x = 2 + √3
therefore
x^2-1/x^2 = (2 + √3)² - 1/(2 + √3)²
x² - 1/x² =[ (7 + 4√3 ) (7 + 4√3 ) -1 ]/(7 + 4√3 )
x² - 1/x² = (97 + 56√3 -1 ) / (7 + 4√3 )
x² - 1/x² =( 96 + 56√3 ) / (7 + 4√3 )
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