x^2+1/x^2=18,find the value of x^3-1/x^3
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2
Answer:
Given x^2 + 1/x^2 = 18.
x^2 + 1/x^2 = 16 + 2
x^2 + 1/x^2 - 2 = 16
(x - 1/x)^2 = 16
(x - 1/x) = 4. ---- (1)
We know that a^3 - b^3 = (a-b)(a^2 + ab + b^2).
x^3 - 1/x^3 = (x - 1/x)(x^2 + x * 1/x + 1/x^2)
= (x - 1/x)(x^2 + 1 + 1/x^2)
= 4 * (18 + 1) (From (1))
= 4 * 19
= 76.
Answered by
0
Answer:
sorry to say that,:;
but I don't know what you mean "
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