Math, asked by ksupreet282, 8 months ago

x^2+1/x^2=18,find the value of x^3-1/x^3​

Answers

Answered by Anonymous
2

Answer:

Given x^2 + 1/x^2 = 18.

         x^2 + 1/x^2 = 16 + 2

        x^2 + 1/x^2 - 2 = 16

        (x - 1/x)^2 = 16

       (x - 1/x) = 4.   ---- (1)

We know that a^3 - b^3 = (a-b)(a^2 + ab + b^2).

x^3 - 1/x^3 = (x - 1/x)(x^2 + x * 1/x + 1/x^2)

                 = (x - 1/x)(x^2 + 1 + 1/x^2)

                = 4 * (18 + 1) (From (1))

                = 4 * 19

                = 76.

Answered by rajeevranjan870965
0

Answer:

sorry to say that,:;

but I don't know what you mean "

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