Question

x^2 +1/x^2-18 spleating of last term
please please please please please please please please please please please please please please please please please please please please please please please please please give answer fast I have exam tomorrow ​

Answer 1

Step-by-step explanation:

Given that :-

x²+1/x²-18

adding and subtracting 2

=>x²+1/x²-2+2+18

=>[(x)²+(1/x)²-2(x)(1/x)]+2-18

(a²-2ab+b²=(a-b)²)

=>(x-1/x)²+2-18

=>(x-1/x)²-16

=>(x-1/x)²-4²

This is in the form of a²-b²

Here a=x-1/x and b=4

=>a²-b²=(a+b)(a-b)

=>(x-1/x)²-4²=(x-1/x+4)(x-1/x-4)

Answer 2

Answer:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

x^2-18-(x-2)=0

Step by step solution :

STEP

1

:

Trying to factor by splitting the middle term

1.1 Factoring x2-x-16

The first term is, x2 its coefficient is 1 .

The middle term is, -x its coefficient is -1 .

The last term, "the constant", is -16

Step-1 : Multiply the coefficient of the first term by the constant 1 • -16 = -16

Step-2 : Find two factors of -16 whose sum equals the coefficient of the middle term, which is -1 .

-16 + 1 = -15

-8 + 2 = -6

-4 + 4 = 0

-2 + 8 = 6

-1 + 16 = 15

Observation : No two such factors can be found !!