X^2+1/x^2+2-2/x=0 then find the value of x+1/x
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Answered by
3
hey mate here is your answer..
x²-x-1=0 => Delta = (-1)² - 4*1*(-1)=5
=> x(1) = (1-sqrt(5))/2, x(2) = (1+sqrt(5))/2
For x(1), x³-2x+1=(16–8*sqrt(5))/8–2*(1-sqrt(5))/2+1=2
For x(2), x³-2x+1=(16+8*sqrt(5))/8–2*(1+sqrt(5))/2+1=2
hope it helps you
x²-x-1=0 => Delta = (-1)² - 4*1*(-1)=5
=> x(1) = (1-sqrt(5))/2, x(2) = (1+sqrt(5))/2
For x(1), x³-2x+1=(16–8*sqrt(5))/8–2*(1-sqrt(5))/2+1=2
For x(2), x³-2x+1=(16+8*sqrt(5))/8–2*(1+sqrt(5))/2+1=2
hope it helps you
Answered by
0
answer is in alalgebric function or it have a numerical value..
in algeric its ans is underroor 2/x
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