x^2+1/x^2=23. find x^3+1/x^3
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Given x^2 + 1/x^2 = 23. ------- (1)
We know that (a + b)^2 = a^2 + b^2 + 2ab.
(x + 1/x)^2 = x^2 + 1/x^2 + 2 * x * 1/x
= x^2 + 1/x^2 + 2. ------- (2)
Substitute (1) in (2)
x^2 + 1/x^2 + 2 = 23 + 2
= 25
(x + 1/x)^2 = 25
x + 1/x = 5.
Given x^3 + 1/x^3 = (x + 1/x)(x^2 - 1 + 1/x^2)
= 5 * (23 - 1)
= 5 * 22
= 110.
Therefore x^3 + 1/x^3 = 110.
Hope this helps!
We know that (a + b)^2 = a^2 + b^2 + 2ab.
(x + 1/x)^2 = x^2 + 1/x^2 + 2 * x * 1/x
= x^2 + 1/x^2 + 2. ------- (2)
Substitute (1) in (2)
x^2 + 1/x^2 + 2 = 23 + 2
= 25
(x + 1/x)^2 = 25
x + 1/x = 5.
Given x^3 + 1/x^3 = (x + 1/x)(x^2 - 1 + 1/x^2)
= 5 * (23 - 1)
= 5 * 22
= 110.
Therefore x^3 + 1/x^3 = 110.
Hope this helps!
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