x^2+1/x^2=27,find (x^2-1/x^2)
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Hi ,
x² + 1/x² = 27----( 1 )
add 2 both sides, we get
x² + 1/x² + 2 = 27 + 2
(x + 1/ x )² = 29-----( 2 )
ii ) subtract 2 both sides of equation ( 1 )
x² + 1 / x² - 2 = 27 - 2
( x - 1/ x )² = 25 -------( 3 )
multiply ( 2 ) and ( 3 ) ,
( x + 1/ x )² ( x - 1 / x)² = 29 × 25
[ (x + 1/x)(x -1/x)]² = 29 × 25
x² - 1/x² = √29 × ( 5 × 5 )
= 5√29
I hope this helps you.
:)
x² + 1/x² = 27----( 1 )
add 2 both sides, we get
x² + 1/x² + 2 = 27 + 2
(x + 1/ x )² = 29-----( 2 )
ii ) subtract 2 both sides of equation ( 1 )
x² + 1 / x² - 2 = 27 - 2
( x - 1/ x )² = 25 -------( 3 )
multiply ( 2 ) and ( 3 ) ,
( x + 1/ x )² ( x - 1 / x)² = 29 × 25
[ (x + 1/x)(x -1/x)]² = 29 × 25
x² - 1/x² = √29 × ( 5 × 5 )
= 5√29
I hope this helps you.
:)
mmcian:
thanks
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