Question

(x^2+1_x^2)=27, then find the value of (x-1_x) and (x-1_x)

Answer 1

HEYA!

If x2+1x2=27. Then findx−1x ?

If x2+1x2=27. Then find x−1x

Algebra

x−1x=±5

Explanation:

just expand, rearrange n substitute,!

(x−1x)2

=x2−2⋅x⋅1x+(1x)2

=x2−2+(1x)2

=x2+1x2−2

since we have the value of x2+1x2 as 27,

=27−2

=25

⇒(x−1x)2=25

⇒x−1x=±5

❤❤HOPE THIS HELPS ❤❤❤