(x^2+1/x^2)-4(x+1/x)+6... factorise
Answers
Answered by
43
x^2+1/x^2=(x+1/x)^2 -2,
(x^2+1/x^2)-4(x+1/x)+6,
=(x+1/x)^2 -2-4(x+1/x)+6,
=(x+1/x)^2-2×2×(x+1/x)+2^2,
=(x+1/x -2)^2
(x^2+1/x^2)-4(x+1/x)+6,
=(x+1/x)^2 -2-4(x+1/x)+6,
=(x+1/x)^2-2×2×(x+1/x)+2^2,
=(x+1/x -2)^2
SravyaK:
Thanks!!
Answered by
4
Answer:
Step-by-step explanation:
x^2+1/x^2=(x+1/x)^2 -2,
(x^2+1/x^2)-4(x+1/x)+6,
=(x+1/x)^2 -2-4(x+1/x)+6,
=(x+1/x)^2-2×2×(x+1/x)+2^2,
=(x+1/x -2)^2
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