Math, asked by SravyaK, 1 year ago

(x^2+1/x^2)-4(x+1/x)+6... factorise

Answers

Answered by anirbanmondal
43
x^2+1/x^2=(x+1/x)^2 -2,
(x^2+1/x^2)-4(x+1/x)+6,
=(x+1/x)^2 -2-4(x+1/x)+6,
=(x+1/x)^2-2×2×(x+1/x)+2^2,
=(x+1/x -2)^2

SravyaK: Thanks!!
Answered by vnsiddhanth
4

Answer:

Step-by-step explanation:

x^2+1/x^2=(x+1/x)^2 -2,

(x^2+1/x^2)-4(x+1/x)+6,

=(x+1/x)^2 -2-4(x+1/x)+6,

=(x+1/x)^2-2×2×(x+1/x)+2^2,

=(x+1/x -2)^2

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