(x^2+1/x^2)-4i(x+1/x)-6
find square root
Answers
Answered by
1
Answer:
x
2
+
x
2
1
−
i
4
(x−
x
1
)−6
=x
2
+
x
2
1
+4ix−4i
x
1
−4−2 (Using
i
1
=−i)
=x
2
+
x
2
1
+4i
2
+2×x×2i−2×
x
1
×2i−2×x×
x
1
----------(Using i
2
=1)
=(x)
2
+(
x
−1
)
2
+(2i)
2
+2×x(
x
−1
)+2×(
x
−1
)×2i+2×x×2i
=(x−
x
1
+2i)
2
(Using (a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ac))
Therefore, square root of x
2
+
x
2
1
−
i
4
(x−
x
1
)−6 is ±(x−
x
1
+2i).
Explanation:
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