Question

(X+2) +[1/X+2] =5 then (X+2)^3+[1/X+2]^3=​

Answer 1

Answer:

x^2 + x = 5

=> (x+3)(x-2)=-1

=> 1/(x+3) = 2-x

Now,

(x+3)^3 + (1/(x+3))^3

=> (x+3)^3 + (2-x)^3

Using a^3 + b^3 = (a+b)(a^2-ab+b^2),

=> (x+3+2-x)((x+3)^2 - (x+3)(2-x) + (2-x)^2)

=> 5*(2*x^2+2*x+12)

Taking 2 common from inside, and replacing x^2 + x = 5,

=> 10*(5+6)

=> 110

Step-by-step explanation:

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