Question

x^2+1/x^2-6
Pls help with this question it is urgent…

Answer 1

$\large \tt {x}^{2} + \frac{1}{ {x}^{2} } - 6 \\ \\ \bf = > {x}^{2} + \frac{1}{ {x}^{2} } = 6 \\ \\ \bf = > { \bigg(x + \frac{1}{x} \bigg)}^{2} - 2 = 6 \\ \\ = > \bf { \bigg( x + \frac{1}{x} \bigg)}^{2} = 6 + 2 \\ \\ = > \bf { \bigg( x + \frac{1}{x} \bigg)}^{2} = 8 \\ \\ = > \bf \: x + \frac{1}{x} = \sqrt{8} = \red{2 \sqrt{2} }$