Math, asked by mrVoid, 9 months ago

x^2+1/x^2=79 find the value of x​

Answers

Answered by mrsonu962
6

Answer:

 \frac{ {x}^{2}  + 1}{ {x}^{2} }  = 79 \\  =  >  {x}^{2}  + 1 = 79 {x}^{2}  \\  =  > 79 {x}^{2}  -  {x}^{2}  = 1 \\  =  > 78 {x}^{2} = 1 \\  =  >  {x}^{2}   =  \frac{1}{78}  \\  =  > x =  \sqrt{ \frac{1}{78 } }  \\  =  > x =  \frac{1}{ \sqrt{78} }

Answered by ᎷíssGℓαмσƦσυs
12

Answer:

=79

=>x

2

+1=79x

2

=>79x

2

−x

2

=1

=>78x

2

=1

=>x

2

=

78

1

=>x=

78

1

=>x=

78

1

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