Question

x^2+1/x^3+3x^2+3x =A/x+1 +B/(x+1)^2 +C/(x+1)^3 then find A-B+C=?​

Answer 1

LHS=(x−a)(x−b)3x;RHS=x−a2+x−b1=(x−a)(x−b)2(x−b)+(x−a)

LHS=RHS

3X=2(x−b)+(x−a)−−1)

let x=a  in the eqn. (1)

3a=2(a−b)

a=−2b

So; a/b=−2/1

a:b=−2:1

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