x^2-1 / x^3 + 9x^2 + 6x + 3
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1
Answer:
Given quadratic polynomial is
9x
2
−6x−3=0
⇒9x
2
−9x+3x−3=0
⇒9x(x−1)+3(x−1)=0
⇒(9x+3)(x−1)=0
⇒x=
3
−1
or1
here,α=
3
−1
andβ=1
also,a=9;b=−6;c=−3
hence,α+β=
3
−1
+1=
3
2
=
9
−(−6)
=
a
−b
and,α.β=
3
−1
.1=
3
−1
=
9
−3
=
a
c
Hence proved
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