Question

(x^2-(1/x))^6 Find the middle term​

Answer 1

Answer:

The general term in the expansion of ( x − 1 2 x ) 6 (x−12x)6 is Tr + 1 = (– 1)r 6Cr x6 – r ( 1 2 x ) r (12x)r = (– 1)r . 6Cr x6 – r . 2 – r x – r = (– 1)r . 6Cr x6 – 2r . 2– r Now the power of binomial expansion being 6, (even), the middle term is ( 6 2 + 1 ) t h (62+1)th term = 4th term. ∴ T4 = T3+1 = (-1)3 . 6C3 x6-6 2-3 = ( − 1 ) × 6 × 5 × 4 3 × 2 × 1 × x 0 × 1 8 = − 5 2Read more on Sarthaks.com - https://www.sarthaks.com/970248/write-the-middle-term-in-the-expansion-of-x-1-2x-6

Step-by-step explanation:

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