Question

(x^2 - 1) (y^2 - 4) + 8xy

Answer 1

Answer:

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Step-by-step explanation:

x2y2−8xy−48

x2y2−12xy+4xy−48

Take out common in all terms we get,

xy(xy−12)+4(xy−12)

(xy−12)(xy+4)

Answer 2

Answer:

[(x)^2 - (1)^2] [(y) ^2 - (2) ^2] + 8xy

(x+1) (x-1) (y+2) (y-2) + 8 xy