x^2-10ix-21=0...here i is iota
Answers
Answered by
0
Answer:
(x-3i)(x-7i)=0
Step-by-step explanation:
x^2-10ix+21i^2=0 i^2=-1
x^2-3ix-7ix+21i^2=0
x(x-3i)-7i(x-3i)=0
(x-3i)(x-7i)=0 Ans
Answered by
0
Answer:
final answer is (x+3) (x-7)
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