Math, asked by bmansar15, 7 months ago

x^2-10ix-21=0...here i is iota​

Answers

Answered by abdulldianoueo4z
0

Answer:

(x-3i)(x-7i)=0

Step-by-step explanation:

x^2-10ix+21i^2=0                i^2=-1

x^2-3ix-7ix+21i^2=0

x(x-3i)-7i(x-3i)=0

(x-3i)(x-7i)=0 Ans

Answered by trickyrahul1999
0

Answer:

final answer is (x+3) (x-7)

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