Question

x^2-10x+21 find the factors of this polynomials

Answer 1

here is ur answer .

x^2-10x+21

= x^2-3x-7x+21

= x(x-3)-7(x-3)

= (x-7)(x-3)

hope it help U dear ✔

@ansika

Answer 2

Answer:

3&7 are the factors

Step-by-step explanation:

x^2-10x+21=0

x^2-7x-3x+21=0

x (x-3)-3 (x-7)=0

(x-3)(x-7)=0

:♢x=3&7