Math, asked by neevbajaj, 4 months ago

x^2 + 10x + 25 - 1/49 x​

Answers

Answered by Anonymous
2

x² + 10x + 25 - 1/49x

x² + 2*5*x + (5)² - 1/49x

(x + 5)² - (1)²/49x

(x + 6)(x + 4)/49x

Answered by ZaraAntisera
0

Step-by-step explanation:

The difference of squares identity can be written:

a^2-b^2 = (a-b)(a+b)

Use this with a=(x-5) and b=7 later.

Given:

x^2-10x+25=49

Both sides of this equation are already perfect squares:

(x-5)^2 = x^2-10x+25 = 49 = 7^2

Subtract 7^2 from both ends to get:

0 = (x-5)^2-7^2 = ((x-5)-7)((x-5)+7) = (x-12)(x+2)

Hence:

x=12" " or " "x = -2

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