x^2 + 10x + 25 - 1/49 x
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x² + 10x + 25 - 1/49x
x² + 2*5*x + (5)² - 1/49x
(x + 5)² - (1)²/49x
(x + 6)(x + 4)/49x
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Step-by-step explanation:
The difference of squares identity can be written:
a^2-b^2 = (a-b)(a+b)
Use this with a=(x-5) and b=7 later.
Given:
x^2-10x+25=49
Both sides of this equation are already perfect squares:
(x-5)^2 = x^2-10x+25 = 49 = 7^2
Subtract 7^2 from both ends to get:
0 = (x-5)^2-7^2 = ((x-5)-7)((x-5)+7) = (x-12)(x+2)
Hence:
x=12" " or " "x = -2
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