Question

X^2-11x+120=0 find the value of x

Answer 1

Step-by-step explanation:

ax^2+bx+c=0

roots.. are.. x=(-b)±(√b^2-4ac)/2a

therefore...

a=1

b= -11

c=120

x=11±(√11^2-4*120*1)/2*1=11±18.9i/2

because √-1=i