Question

x^2 + 12x - 160 = 0 where x is the original natural number.

Answer 1

Answer:

$x = - 20 \: or \: x = 8$

Step-by-step explanation:

${x}^{2} + 12x - 160 = 0$

${x}^{2} + 20x - 8x - 160 = 0$

$x(x + 20) - 8( x + 20)$

$(x + 20)(x - 8)$

$x + 20 = 0 \\ x = - 20$

$x - 8 = 0 \\ x = 8$