Question

X*2-12X+32=0 FIND THE NATURE OF ROOTS

Answer 1

Step-by-step explanation:

${x}^{2} - 12x + 32 \\ comparing \: by \: a {x}^{2} + bx + c \\ a = 1 \: \: b = -1 2 \: \: \: c = 32 \\ for \: nature \: of \: roots \\ \sqrt{ {b }^{2} - 4ac} = \sqrt{ {( - 12)}^{2} - 4 \times 1 \times 32 } \\ = \sqrt{144 - 128} \\ \sqrt{16} = 4 \\ \sqrt{ {b}^{2} - 4ac } \geqslant 0 \: hence \: roots \: are \: real \:$

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Answer 2

Answer:

x=8 and x=4

Step-by-step explanation:

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