x^2+16x-9=0 by completing squaring method
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Answer:
x = ±√73 - 8
Step-by-step explanation:
'Completing the square'
⇒ Consider the polynomial given in the question.
- x² + 16x - 9 = 0
⇒ Add 9 to both sides.
- x² + 16x = 9
⇒ Now to complete the square, we have to add the square of half the coefficient of x to both sides. Here the coefficient of x is 16, so (16/2)² = 8² = 64 should be added.
- x² + 16x + 64 = 9 + 64
⇒ Factorise the LHS.
- (x + 8)² = 73
⇒ Take the square roots of both.
- x + 8 = ±√73
⇒ Now subtract 8 from both sides.
- x = ±√73 - 8
- x = √73 - 8 OR x = -√73 - 8
⇒ Thus the value of x is √73 - 8 or -√73 - 8.
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