Question

x^2-17x+72 factorise algebraic expressions​

Answer 1

Answer:

$= > {x}^{2} - 17x + 72 \\ \\ = > {x}^{2} - (9 + 8)x + 72 \\ \\ = > {x}^{2} - 9x - 8x + 72 \\ \\ = > x(x - 9) - 8(x - 9) \\ \\ = > (x - 9)(x - 8)$

Answer 2

The correct answer is "x = 9" and "x = 8".

Step-by-step explanation:

$The \ given \ equation \ is:\\\\x^2-17x+72\\\\On \ factorizing \ the \ above \ equation,we \ get\\\\x^2-9x-8x+72=0\\\\x(x-9)-8(x-9)=0\\\\(x-9)(x-8)=0\\\\x-9=0\\\\x=9\\\\Or,\\\\x-8=0\\\\x=8$

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