Math, asked by nakulbokade19, 5 hours ago

x ^ 2 - 18x + 32 = 0

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Answers

Answered by bigdashezada61
16

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Use the quadratic formula

=

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x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

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x^{2}-18x+32=0

x2−18x+32=0

=

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a={\color{#c92786}{1}}

a=1

=

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b={\color{#e8710a}{-18}}

b=−18

=

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c={\color{#129eaf}{32}}

c=32

=

(

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Answered by MrFeast
1

 \blue{  \Large{\boxed{ \tt{ \red{Answer : }}}}}

 {x}^{2}  - 18x + 32 = 0 \\  {x}^{2}  - 18x = 0 + 32 \\  {x}^{2}  - 18x = 32 \\  {x}^{2}   - x =  \frac{32}{18}  \\  {x}^{2}  - x = 1.77778

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