Question

x+2^⅓+2^⅔=0 then the value of x³+6=?​

Answer 1

Answer:

answer is 15x mark me brainliest

Answer 2

Answer:

$(x + {2}^{ \frac{1}{3} } ) + {2}^{ \frac{2}{3} } = 0$

$x + 2(1 {}^{ \frac{1}{3} } + 1{}^{ \frac{2}{3} } ) = 0$

$x + 2(0.3 + 0.3) = 0$

$x + 1.32 = 0$

$x = - 1.32$

now,

${x}^{3} + 6$

$( - 1.32) {}^{3} + 6$

$- 2.29 + 6$

$3.700$