Question

(x-2)^2+1=2x-3 find roots​

Answer 1

Answer:

the answer is in the attachment

Answer 2

Answer:

4,2

Step-by-step explanation:

$\displaystyle (x-2)^2 +1=2x-3\\\\x^2 +4 -4x +1 = 2x - 3\\\\x^2 -6x + 8=0\\\\(x-4)(x-2)=0\\\\\therefore \text{The roots are } 4 , 2$