Question

(x+2)^2 - 14 (x+2) +45=0 ch quadratic equation
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Answer 1

Answer:

Step-by-step explanation:

(x+2)²-14(x+2)+45=0

Let (x+2)=a

So the equation reduces to

a²-14a+45=0

=>a²-5a-9a+45=0

=> a(a-5)-9(a-5)=0

=> (a-5)(a-9)=0

=> a=5 or a=9

=> x+2=5 or x+2=9

=> x=5-2 or x=9-2

=> x=3 or x=7

So x=3 ,x=7 are the solutions of the equation.

Hope you got it.