Question

x^2+2*√2-6=0
Find roots and verify with coefficients

Answer 1

Here Is Your Ans ⤵

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${x}^{2} + \sqrt[2]{2x} - 6 \\ \\ {x}^{2} + \sqrt[3]{2x} - \sqrt{2x} - 6 \\ \\ x(x + \sqrt[3]{2} ) - \sqrt{2} (x + \sqrt[3]{2} ) \\ \\ x \: = \sqrt{2} \: \: and \: \: x \: = - \sqrt[3]{2}$

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