Question

x^2+2√2-6=0
how to solve this problem​

Answer 1

Step-by-step explanation:

x^2+2√2x-6=0

x^2+3√2x-√2x-6=0

x(x+3√2)-√2(x+3√2)=0

(x-√2)(x+3√2)=0

Answer 2

I think your question is

find the root of this function f ( x ) = x² + 2√2x - 6

$x^2+2√2-6=0 \\ \\ \odot \: \bf \: \: as \: \: we \: \: know \\ \\ : \longrightarrow x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ \natural \: \bf \: \: putting \: \: values \: \: \\ \\ : \longrightarrow x = \frac{ - 2 \sqrt{2} \pm \sqrt{ ({2 \sqrt{2}) }^{2} - 4 \times 1 \times ( - 6)} }{2 \times 1} \\ \\ \\ : \longrightarrow x = \frac{ - 2 \sqrt{2} \pm \sqrt{32} }{2} \\ \\ \\ \underline {\bigstar \: \: \: { \bf : \longrightarrow x = \sqrt{2} } \: \: \: \: \bigstar }$