Math, asked by wannaknowmore3421, 10 months ago

∫√{(x+2)² + 2} dx का मान ज्ञात कीजिए।

Answers

Answered by jitendra420156
0

\int \sqrt{(x+2)^2+2} dx

= \frac{1}{2}(x+2)\sqrt{(x+2)^2+2}  +\frac{1}{2}\times 2 log(x+\sqrt{(x+2)^2+2})+C

Step-by-step explanation:

\int \sqrt{(x+2)^2+2} dx

= \frac{1}{2}(x+2)\sqrt{(x+2)^2+2}  +\frac{1}{2}\times 2 log(x+\sqrt{(x+2)^2+2})+C

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