Question

(x-√2)^2-2(x+1)=0 please answer for this​

Answer 1

Answer:

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2x² - 2√2x + 1 = 0

2x² - √2x - √2x + 1 = 0

√2x ( √2x - 1 ) - 1 ( √2x - 1 ) = 0

( √2x - 1 ) ( √2x - 1 ) = 0

* ( √2x - 1 ) = 0

x = 1/√2

* ( √2x - 1 ) = 0

x = 1/√2

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