Question

((x-2)^2 -2 )((x-2)^2 +2) find fhe value of x at a minimum value

Answer 1

Answer:

Step-by-step explanation:

use formula

(a+b)(a-b)=$(a+b)(a-b)=a^2-b^2\\a=(x-2)^2-2\\b=a=(x-2)^2+2\\((x-2)^2-2)((x-2)^2+2)=((x-2)^2)^2-2^2=(x-2)^4-4\\so (x-2)^4 is always a positive number. \\our fuction will give minimum value at x=2$