Math, asked by mohitdayalani3755, 20 days ago

(x+2)^2=2x^2 what is the value o x?

Answers

Answered by PrinceMishra18
0

Step-by-step explanation:

(x+2)² = 2x²

or, x² + 4x + 4 = 2x²

or, x² - 4x - 4 = 0

or, x = - b ± √ b² - 4ac

2a

= 4 ± √ 16 - 4.1.4

2

= 4 ± √ 1

2

= 4 + 1 , 4 - 1

2 2

= 5/2 , 3/2

Answered by pnareshkumar35
0

Answer:

x=4

Step-by-step explanation:

2x^+8+4.x. 4=4x^

2x^-4x^+16x=8

-2x^+6x+8

(-2x^+8x)(-2x+8)

-2x(x-4) -2(x-4)

(-2x-2)(x-4)

-2x-2=0

-2x=2

x=2/-2

x=-1

or

x-4=0

x=4

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