X^2+2√2x-6=0 solve by quadratic formula
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given: x² + 2√2 x - 6 = 0
to find: value of x
a = 1, b = 2√2, c = - 6
=> x = [- b ± √(b² - 4ac)] / 5a
=> x = [- 2√2 ± √( 2√2)² - 4(1)(-6)] / 2*1
=> x = [-2√2 ± √ (8 + 24)] / 2
=> x = [-2√2 ± √(32)] / 2
=> x = [-2√2 ± 5.66] / 2
=> x = (-2√2 + 5.66) / 2 = 1.416
=> x = (-2√2 - 5.66) / 2 = - 4.244
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