Math, asked by ramshanarzo, 4 months ago

(x^2 - 2/3) (x^2+4/3) write in standard form by process​

Answers

Answered by beenamanu
0

Answer:

( X^2 - 2 /3) (x^2 + 4 / 3)

= x^2 (-2 / 3 + 4 / 3)

= x^2 * 2 / 3

= 2x^2 / 3

Answered by richadhupar1977
0

Answer:

(x²-2/3) (x²+4/3)

x²(x²+4/3) -2/3(x²+4/3)

x⁴+4/3x-2/3x²-8/9

Standard form = x⁴-2/3x²+4/3x-8/9

Hope it helps..

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