Question

x^2 +2√(3)x -9 =0
Factorise and get the value of x either in integer or in fraction

Answer 1

hii......friend

the answer is here,

$= > {x}^{2} + 2 \sqrt{3} x - 9 = 0$

$= > \: {x}^{2} + 3 \sqrt{3} x - \sqrt{3} x - 9 = 0$

$= > \: x(x + 3 \sqrt{3} ) - \sqrt{3} (x + 3 \sqrt{3} ) = 0$

$= > \: (x - \sqrt{3} )(x + 3 \sqrt{3} ) = 0$

So,

$= > \: x = \sqrt{3} \: \: and \: \: - 3 \sqrt{3}$


:-)Hope it helps u.

Answer 2

Heya dear !!!



X² + 2✓3 X - 9 = 0



X² + 3✓3X - ✓3 X - 9 = 0



X ( X+3✓3) - ✓3 ( X + 3✓3) = 0




( X + 3✓3) ( X - ✓3) = 0



( X + 3✓3) = 0 OR ( X - ✓3) = 0




X = -3✓3 OR X = ✓3.





:-)....... HOPE IT WILL HELP YOU....... :-)