Question

x/2+2/3y=-1 and x-1/3y=3 find elimination method​

Answer 1

2/x + 2/3y = 1/6

2/x + ( 2/y ) × 1/3 = 1/6 ---( 1 )

3/x + 2/y = 0

2/y = - 3/ x ------( 2 )

Put ( 2 ) in equation ( 1 ) ,

2 / x + ( - 3 / x ) × 1/3 = 1/6

2/x - 1/x = 1/6

1 / x = = 1/6

x = 6 ----( 3 )

Put ( 3 ) in equation ( 2 ),

2 / y = ( - 3 / 6 )

2/y = - 1/2

1 / y = - 1 / 4

y = - 4

Therefore ,

x = 6 ,

y = - 4